Java Program To find A Number is ArmStrong or Not ?

Here we are going to write a program to check a number is ArmStrong or not ?

Number is ArmStrong or not ?

[java]

import java.util.Scanner;

public class ArmStrongNumber {

public static void main(String a[]) {

       int remainder, dividor, sum = 0;
       Scanner sc = new Scanner(System.in);
       System.out.println("Enter a Number");
       int input = sc.nextInt();
       int temp = input;

       while (input > 0) {
           remainder = input % 10;
           input = input / 10;
           sum = sum + (remainder * remainder * remainder);
       }
       if (sum == temp) {
           System.out.println("ArmStrong Number");
       } else {
           System.out.println("Not an ArmStrong Number");
       }

}
}

[/java]

Output :

Enter a Number 371
ArmStrong Number
Enter a Number 180
Not an ArmStrong Number

Happy Learning 🙂